Question

suman gives 1/5 of a chocolate bar to anand and 3/8 of it to meenakahi.what fraction of chocolate is left with suman?​

Answer 1

Fraction left with suman is (1-(1/5+3/8)=1-(8+15/40)=40-23/40=17/40

Answer 2

$\frac{17}{40}$ of chocolate bar is left with suman.

Step-by-step explanation:

Given :

• Suman gives 1/5 of a chocolate bar to anand.
• Suman gives 3/8 of a chocolate bar to meenakahi.

Let the chocolate bar has quantity x.

$= > s + \frac{x}{5} + \frac{3x}{8} = x$

$= > s + \frac{8x + 3x \times 5}{40} = x$

$= > s + \frac{8x + 15x}{40} = x$

$= > s + \frac{23x}{40} = x$

$= > s = x - \frac{23x}{40}$

$= > s = \frac{40x - 23x}{40}$

$= > s = \frac{17x}{40}$

[tex] \frac{17}{40} [/tex] of chocolate bar is left with suman.