Math, asked by nits78, 1 year ago

suman had 24 sweets,kiran had 36 sweets and peer to 15 sweets .simian ate 8sweets,kiran 12 and peer to ate 5 sweets.what friction of their own sweets did each have

Answers

Answered by niyatinehal58
2
Suman ate 8/24= 1/3
Kiran ate 12/36= 1/3
Peer ate 5/15= 1/3
Hope that helped

nits78: answer is 2/3 how explain
Answered by PravinRatta
1

Answer:

2/3 fraction of their own sweets each have.

Step-by-step explanation:

Total sweet Suman had = 24

Suman Ate = 8 sweet

Now she have 16 sweet.

Fraction of sweet Suman have = 16/24 = 2/3

Total sweet Kiran had = 36

Kiran Ate = 12 sweet

Now she have 24 sweet.

Fraction of sweet Kiran have = 24/36 = 2/3

Total sweet Peer had = 15

Peer Ate = 5 sweet

Now she have 10 sweet.

Fraction of sweet Peer have = 10/15 = 2/3

2/3 fraction of their own sweets each have.

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