Math, asked by sjha68227, 6 hours ago

Suman has 5 clothes of different types, say, C₁,C₂, ...,C₅ and she wants to wear all these clothes at different days, say, D₁,D₂,...,D₅. Due to some reason, C₁ must be used either at D₃ or at D₄ and C₂ can be used either at D₄ or at D₃ or at D₅. Every cloth is to be used at only one day, in how many ways can clothes be used?

Answers

Answered by laxmilucky0606
1

Answer:

Suman has 5 clothes of different types, say, C₁,C₂, ...,C₅ and she wants to wear all these clothes at different days, say, D₁,D₂,...,D₅. Due to some reason, C₁ must be used either at D₃ or at D₄ and C₂ can be used either at D₄ or at D₃ or at D₅. Every cloth is to be used at only one day, in how many ways can clothes be used?

2

Answered by amitnrw
3

Given: Suman has 5 clothes of different types, say, C₁,C₂, ...,C₅ and she wants to wear all these clothes at different days, say, D₁,D₂,...,D₅. Due to some reason, C₁ must be used either at D₃ or at D₄ and C₂ can be used either at D₄ or at D₃ or at D₅. Every cloth is to be used at only one day,  

To Find :  in how many ways can clothes be used

Solution:

Clothes C₁,C₂, ... ,C₅

Days D₁,D₂,...,D₅

C₁ must be used either at D₃ or at D₄

case 1 :  C₁   used on D₃  

case 2 :  C₁   used on D₄

case 1 :    C₁   used on D₃  

C₂ can be used either at D₄ or at D₃ or at D₅.

D₃   is already gone  so two subcases further

C₂  is used on  D₄ or D₅  

then remaining 3 clothes can wear on 3 days  in 3!  = 6 ways

Hence 2 * 6  = 12   ways

case 2 :    C₁   used on D₄  

C₂ can be used either at D₄ or at D₃ or at D₅.

D₄   is already gone  so two subcases further

C₂  is used on  D₃ or D₅  

then remaining 3 clothes can be wear in 3!  = 6 ways

Hence 2 * 6  = 12   ways

Total ways = 12 + 12 = 24 Ways

Clothes can be used in 24 ways

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