Math, asked by pkjain351, 1 month ago

Suman has a piece of land, which is in the shape of a rhombus. She wants her two sons to work on the land and produce different crops. She divides the land in two equal parts by drawing a diagonal. If its perimeter is 400 m and one of the diagonals is of length 120 m, how much area each of them will get for his crops ?​

Answers

Answered by Yoursenorita
5

QUESTION:

  • Suman has a piece of land, which is in the shape of a rhombus. She wants her two sons to work on the land and produce different crops. She divides the land in two equal parts by drawing a diagonal. If its perimeter is 400 m and one of the diagonals is of length 120 m, how much area each of them will get for his crops ?

ANSWER:

4800m^2

EXPLANATION:

  • We find it using the HERON'S FORMULA

  • Since perimeter of Rhombus = 400 m

  • each side = 100 m

  • Using Pythagoras theorem

AO^2 = 100^2 - 80^2

AO^2= 10000-6400

AO^2 = 3600

 {ao}^{2}   = \sqrt{3600}

AO = 60 M

AC = 2(AO) =120

Area of Rhombus = 1/2 * Product of diagonals

= 1/2 * 160 * 120 = 9600 m^2

The area that each of the children get

= 9600/2

= 4800 m^2

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