Suman left 1/5 of her property for her eldest son, 1/6 of her property for her second son and 5/6 of the remaining to her daughter, how much was left over?
Answers
Answer:
19/180
Step-by-step explanation:
Given:-
Property given to the eldest son = 1/5
Property given to second son = 1/6
Total part given to both
⇒ 1/5 + 1/6
⇒ 11/30
Remaining part
⇒ 1 - (11/30)
⇒19/30
Part given to daughter
⇒ (5/6) of (19/30)
⇒ (19/30) - (19/36)
⇒ (114 - 95)/180
⇒ 19/180
Hence, 19/180 part was left over .
Suman left 1/5 of her property for her eldest son, 1/6 of her property for her second son and 5/6 of the remaining to her daughter, how much was left over?
First of all we will assume the total property of Suman is 1.
Now the property left by Suman for his eldest son is 1/5.
Again,the property left by Suman for his second son is 1/6.
So the total property left for both of his son is=1/5+1/6 i.e =11/30
Remaining property left after his son is =1–(11/30) i.e equals to 19/30
Now according to questions 5/6 of remaining property (19/30) is left for his daughter
So daughter's property=
Here,property left will be=