Question

suman reads 1/3 of a storybook on the firat day and 1/4 of the book on the second day . what part of the book is yet to be read by suman?

Answer 1

Hey mate!!!!

First of all we should find the sum of both parts

So total book read by Suman =
$\frac{1}{3} + \frac{1}{4}$
Taking out the LCM. We have
$\frac{1}{3} + \frac{1}{4} \\ \\ = \frac{4}{12} + \frac{3}{12} = \frac{7}{12}$
Suman had read 7/12.
Now the part remaining=
$1 - \frac{7}{12} \\ \\ because \: a \: fraction \: as \: a \: whole \: is \: 1$
So we have
$1 - \frac{7}{12} \\ \\ = \frac{12}{12} - \frac{7}{12} \\ \\ = \frac{5}{12}$
5/12 of the book is remaining.


Hope it helps dear friend ☺️✌️✌️

Answer 2

Answer:

First of all we should find the sum of both parts

So total book read by Suman =

\frac{1}{3} + \frac{1}{4}

3

1

+

4

1

Taking out the LCM. We have

\begin{gathered} \frac{1}{3} + \frac{1}{4} \\ \\ = \frac{4}{12} + \frac{3}{12} = \frac{7}{12} \end{gathered}

3

1

+

4

1

=

12

4

+

12

3

=

12

7

Suman had read 7/12.

Now the part remaining=

\begin{gathered}1 - \frac{7}{12} \\ \\ because \: a \: fraction \: as \: a \: whole \: is \: 1\end{gathered}

1−

12

7

becauseafractionasawholeis1

So we have

\begin{gathered}1 - \frac{7}{12} \\ \\ = \frac{12}{12} - \frac{7}{12} \\ \\ = \frac{5}{12} \end{gathered}

1−

12

7

=

12

12

−

12

7

=

12

5

5/12 of the book is remaining.

Hope it helps dear friend ☺️✌️✌️