Question

suman split a bag of chocolates amongst four children. payal got 7/15 , subha got 7/8, raj got 7/20 and lata got 7/10. arrange the name of the children in the order who got from least to greatest number of chocolates.​

Answer 1

Answer:

Let first number be x.

According to the question second number is x + 1 and the third is x + 2

Sum of first and second numbers = (x) + (x + 1).

According to question:

⇒ (x) + (x + 1) = 15 + (x + 2)

⇒ 2x + 1 = 17 + x

Transposing x to LHS and 1 to RHS, we get

⇒2x – x = 17 – 1

⇒ x = 16

So, first number = x = 16,

Second number = x + 1 = 16 + 1 = 17

And third number = x + 2 = 16 + 2 = 18

Thus, the required consecutive natural numbers are 16, 17 and 18.

Answer 2

Answer:

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