Suman split a bag of chocolates amongst four children. Payal got
![\frac{7}{15} \frac{7}{15}](https://tex.z-dn.net/?f=+%5Cfrac%7B7%7D%7B15%7D+)
, Shubh got
![\frac{7}{8} \frac{7}{8}](https://tex.z-dn.net/?f=+%5Cfrac%7B7%7D%7B8%7D+)
. Raj got
![\frac{7}{20} \frac{7}{20}](https://tex.z-dn.net/?f=+%5Cfrac%7B7%7D%7B20%7D+)
and Lata got
![\frac{7}{10} \frac{7}{10}](https://tex.z-dn.net/?f=+%5Cfrac%7B7%7D%7B10%7D+)
. Arrange the names of the children in the order who got from least to greatest number of chocolates.
EXPLAIN and explain fr class 6
Answers
Answered by
0
Answer:
1. Shubh
2.Lata
3.Payal
4.Raj
Answered by
1
Step-by-step explanation:
Given : payal got 7/15 , Shubh got 7/8 , Raj got 7/20 and lata got 7/10
Here we will take the lcm of all of these
56 , 105 , 42 , 84
--------------------------
120
Hence , Payal = 56/120
Shubh = 105 /120
Raj = 42/120
Lata = 84/120
In order to from least to the greatest :
Raj<payal<lata<Shubh
Hope it helps you !!!
Similar questions
Math,
3 months ago
Math,
3 months ago
English,
6 months ago
India Languages,
6 months ago
India Languages,
1 year ago
Math,
1 year ago