Question

Sumit and his friend Bhargav appear in an interview for two vacancies in the same post. The probability of Sumit's selection is (1/7) and the probability of Bhargav's selection is (1/5). What is the probability that only one of them is selected ?

Answer 1

Answer:

11 / 35.

Step-by-step explanation:

Using the first theorem of probability, we know that for any two events A and B that are not affected or governed by each other, the probability of both events taking place together P(A+B) when P(A) is the probability of A only taking place and P(B) is the probability of only B taking place, is given as follows,:

P(A+B) = P(A) x P(B)

Also, the probability theorem states that the probability of only either of the two mutually exclusive events taking place is:

P(A or B only) = P(A) + P(B) – P(A+B)

Substituting known values, we get the answer to be:

P(A or B only) = 11 / 35

Answer 2

plz mArk as brainliest

refer to the pic to know answer

if handwriting isn't good, sorry❤