Question

Sumit cut a wire into two equal parts. one part he bent in the form of square and other part bent in the form of circle. if the area of circle exceeds that of the square by 33 sq.cm ..then what is the original legth of the wire?​

Answer 1

Answer:

length of wire = 2x = 62.2 cm

Step-by-step explanation:

Let say length of wire was 2x

Perimeter of circle = x meter

Perimeter of square = x meter

area of square + 33 = area of circle

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Perimeter of circle = x meter

2$\pi$r = x

r = x/2$\pi$

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Perimeter of square = x meter

4* side = x

side = x/4

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area of square + 33 = area of circle

$side^{2} + 33 = \pi r^{2}$

$\frac{x^{2} }{16}$ + 33 = $\pi * (x/2\pi) ^{2}$

x = 31.1 cm

length of wire = 2x = 62.2 cm

Answer 2

please see the attached picture to know the full step by step solution.