Sumit evacuated a cylinder and filled in 4g of gas A at temperature 25˚C. Pressure was found to
be 1 atm. His friend Vineet, filled another 8g of gas B in the cylinder at the same temperature. The
final pressure was found to be 1.5 atm. The ratio of molecular masses of A and B (assuming ideal
gas behaviour) is
a) 1 : 1 b) 1 : 2 c) 1 : 3 d) 1 : 4
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Using
PV= nRT
For gas A only
1 x V=nART
or
V = (4/MA)RT..............(1)
After addition of gas B.
1.5V=(nA+nB)RT
or
1.5V=(4/MA+8/MB)RT................(2)
Now dividing eq. (2) by e.q(1) and solving we get..
MA/MB= 1/2
PV= nRT
For gas A only
1 x V=nART
or
V = (4/MA)RT..............(1)
After addition of gas B.
1.5V=(nA+nB)RT
or
1.5V=(4/MA+8/MB)RT................(2)
Now dividing eq. (2) by e.q(1) and solving we get..
MA/MB= 1/2
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