Question

Sumit is 3 times as old his son. Five year later he shall we two and a half times as old as his son. How old is sumit at present. ​

Answer 1

Step-by-step explanation:

Given:-

• Sumit is 3 times as old as his son.

• Five years later, Sumit will be two and half times as old as his son.

To Find:-

• The present age of Sumit.

Solution:-

Let the age present of Sumit's son be x

As, Sumit is three times as old as his son.

Present age of Sumit = 3x

Five years later:-

Age of Sumit's son = x + 5

Age of Sumit = 3x + 5

Given, He will be 2½ times as old as his son.

$\sf \implies3x + 5 = 2 \frac{1}{2} ( x + 5)$

$\sf \implies3x + 5 = \dfrac{5}{2} ( x + 5)$

$\sf \implies2(3x + 5) = 5( x + 5)$

$\sf \implies6x + 10= 5x + 25$

$\sf \implies 6x - 5x = 25 - 10$

$\sf \implies x = 15$

Present age of Sumit's son = 15 years

Present age of Sumit = 3x

= 3 × 15

= 45

$\underline{\boxed{\sf \therefore Present\: age\: of\: Sumit = 45\: years}}$

Answer 2

Answer:

45 years.

Step-by-step explanation:

Let's the age of sumit is x yrs and,

the age of his son is y yrs.

So, we know that x = 3y ----- (i)

According to the question:

Sumit.

2(x +5) = 5(y +5)

=) 2x + 10 = 5y + 25

2x = 5y + 15

Son.

2(3y) = 5y +15

=) 6y = 5y + 15

y = 15.

Substituting value in equation-----(i)

x = 3×15

x = 45 years. Answer.

Hope it helps you