Question

sumit is 5years younger than,his Brother rohit four years later rohit will be twice as old as sumit.find their present ages​

Answer 1

let rohit be x

sumit be x-5

ATQ

after 4 years

rohit = x+4

sumit = x-5+4 = x-1

= x+4 = 2 (x-1)

x+4 = 2x-2

x-2x = -2-4

-x = -6

x=6

rohit = 6 years

sumit = 1 years

Answer 2

The present age of Rohit is 6 years and the present age of Sumit is 1 year

Step-by-step explanation:

Let the present age of Rohit be x years

We are given that Sumit is 5 years younger than,his Brother Rohit

So, Sumit's present age = x-5 years

Rohit's age after 4 years = x+4

Sumit's age after 4 years = x-5+4=x-1

We are given that four years later rohit will be twice as old as sumit

So, x+4=2(x-1)

x+4=2x-2

6=x

Rohit's present age = 6 years

Sumit's present age = x-5=6-5=1 year

Hence The present age of Rohit is 6 years and the present age of Sumit is 1 year

#Learn more:

The sum of the ages of two brothers is 41years 5years later the elder brother will be twice as old as the younger find their present

https://brainly.in/question/7876195