Math, asked by 170234vaanya, 3 months ago

SUMIT WALKS AROUND A SQUARE PARK OF SIDE 20 M WHILE AMIT WALKS STRAIGHT PARK OF LENGTH 16M AND WIDTH 15 WHO WALK LONG AND HOW MUCH ?

Answers

Answered by rajputkrishn17
1

Answer:

Sumit walks the most by  18 m

Step-by-step explanation

the perimeter of a square is S x 4

here the side is 20m

hence it's (20x4)

that's 80m

the perimeter of a rectangle is 2(l+b)

length is 16m And breadth is 15m

hence 2(16+15)

2(31)

and that is 62 m, now when we subtract it's 80-62 and that is 18

bye

Answered by mm192117gmailcom
1

Answer: Sumit

Sumit:

Perimeter of a square park = 4×20m

= 80m

Sumit walks 80m.

Amit:

Length 16m

Width 15m

= 2 ( l + b)

= 2 ( 31)

= 31 × 2

= 62m

Amit walks 62m.

SUMIT walks more than AMIT

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