Math, asked by merajsp, 8 hours ago

Sumitra has 34 in 50-paise and 25-paise coins. If the number of 25-paise coins is twice the number of 50-paise coins, how many coins of each kind does she have? ​

Answers

Answered by NightSparkle
7

\large\bold{\underline{\underline{\red{✎Given:-}}}}

  • Sumitra has 34 in 50-paise and 25-paise Coins .If The number of 25-paise Coin's is twice the number of 50-paise coins , how many coin's of each kind does have ??

\large\bold{\underline{\underline{\red{❒ \:  ꜱᴏʟᴜᴛɪᴏɴꜱ:-}}}}

Let's the number of 50 paise coin's = 'x'

Then the number of 20 paise coin's = 2x,

According to give Questions :-

\red{ \boxed{\sf{x \times 0.50 + 2 x \times 0.25 = 34   }}}

\red{ \boxed{\sf{ =  >  \: 0.5x + 0.5x = 34 }}}

\red{ \boxed{\sf{x = 34}}}

Hence number of 50 pause coin = 34

Number of 25 praise is = 34×2 = 68.

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Answered by OoAryanKingoO78
4

Answer:

\large\bold{\underline{\underline{\red{✪Given:-}}}}

Sumitra has 34 in 50-paise and 25-paise Coins .If The number of 25-paise Coin's is twice the number of 50-paise coins , how many coin's of each kind does have ??

\large\bold{\underline{\underline{\red{❒ \:  Sᴏʟᴜᴛɪᴏɴꜱ:-}}}}

Let's the number of 50 paise coin's = 'x'

Then the number of 20 paise coin's = 2x,

According to given Questions :-

\purple{ \boxed{\sf{x \times 0.50 + 2 x \times 0.25 = 34   }}}

\green{ \boxed{\sf{ =  >  \: 0.5x + 0.5x = 34 }}}

\pink{ \boxed{\sf{x = 34}}}

Hence number of 50 pause coin = 34

Number of 25 praise is = 34×2 = 68.

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