Sumitra has rs.34 in 50 Paise and25paise coins . If the number of 25 Paise coins is twice the number of 50Paise coins, how many coins of each kind dose she have?
Answers
Answer:
The number of 50 Paise coin = 34
The number of 25 Paise coin = 68
Step-by-step explanation:
Let,
The number of 50 Paise coin = x
The number of 25 Paise coin = 2x
Total amount = Rs 34
Rs. 1 = 100 Paise
34 × 100
3400 paise
★ Value of coin :
50 Paise coin = x
50x
25 Paise coin = 2x
2x × 25
50x
★ According to the question :
⇒ 50x + 50x = 3400
⇒ 100x = 3400
⇒ x = 3400 / 100
⇒ x = 34
★ Value of 2x :
⇒ 2 (34)
⇒ 2 × 34
⇒ 68
Therefore,
The number of 50 Paise coin = 34
The number of 25 Paise coin = 68
Given :
- Sumitra has Rs 34.
- In 50 Paise and 25 Paise coins.
- If the number of 25 Paise coins twice the number of 50 Paise coins.
To find :
- How many coins of each kind does she have.
According to the question,
Let the number of 50 Paise coins be x
And the number of 25 Paise coins be 2x
Total money she have 34
→ As we know that,
Rs 1 = 100 Paise
.°. Rs 34 = 100 × 34
= 3400 Paise
→ Value of Rs 50 coins
→ 50x
→ Value of Rs 25 coins
→ 2x × 25
→ 50x
_________________.....
Now,
→ 50x + 50x = 3400
→ 100x = 3400
→ x = 3400 ÷ 100
.°. x = 34
_________________....
Value of x :-
→ 34
_________________...
Value of 2x :-
→ 2x
→ 2 × 34
→ 68