Summation of iota 2n +1
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+ 2n-1 = 2n – 1. We need to show that P(n + 1) holds, meaning that the sum of the first n + 1 powers of two is numbers is 2n+1 – 1. the sum of the first zero powers of two is 20 – 1. Since the sum of the first zero powers of two is 0 = 20 – 1, we see P(0) is true.
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