Question

summation of numbers 1to1000000..​

Answer 1

summation of numbers 1to1000000..

numbers 1 to 1000000

are in ap

a = 1

d = 1

n = 1000000

sum = (n/2)(a + a +(n-1)d)

= (1000000/2)(1 + 1+ 999999)

= 500000 × 1000001

= 500000500000

1000000..... if zeros are for n time

then summation is

5(n-1)times05(n-1)times0

for n = 1

55

for n = 2

5050

for n=3

500500

and so on.

Answer 2

summation of numbers 1to1000000..

numbers 1 to 1000000

are in ap

a = 1

d = 1

n = 1000000

sum = (n/2)(a + a +(n-1)d)

= (1000000/2)(1 + 1+ 999999)

= 500000 × 1000001

= 500000500000

1000000.. if zeros are for n time

then summation is

5(n-1)times05(n-1)times0

for n = 1

55

for n = 2

5050

for n=3

500500 and so on.