Summer Vacation in
10. 1. Find the area of quadrilateral ABCD in which AB = 12 cm, BC = Y UI,
CD= 10 cm, DA = 7 cm and diagonal AC = 15 cm.
Q. 2. The sides of a quadrilateral ABCD are 6cm, 8cm, 12cm and 14cm (taken in
order) respectively and the angle between the first two sides is a right angle.
Find its area.
0.3. A field in the form of a parallelogram has sides 60m and 40m and one of its
diagonals is 80m long. Find the area of the parallelogram.
10. 4. A rhombus shaped sheet with perimeter 40cm and one diagonal 12cm is
painted on both sides at the rate of Rs. 5 perm'. Find the cost of painting.
10. 5. The perimeter of a right triangle is 40 cm and its hypotenuse is 17 cm.
Calculate its area and verify the result by using Heron's formula.
10. 6. If area of an isosceles triangle is 60 m and its equal side is 13cm, find.
(i) base of the triangle (ii) height of the triangle
Q. 7. Find fire rational numbers between 2/5 and 1/2.
Q. 8. Rationalize the denominator of.
(
11
1 315 + v3
Answers
Answer:
Q.2. draw AB=6cm,BC=8cm,CD=12cm,DA=14cm
join diagonal AC
- (A.T.Q)the angle between first two sides is 90 degree
angle ABC=90 degree
area of triangle ABC=1/2×AB×BC
=1/2×6×8
=24cm ^2
In triangle ABC
(AC)^2=(AB)^2+(BC)^2
(AC)^2 =(6)^2+(8)^2
(AC)^2 =36+64
(AC)^2 =100
AC =√100
=10cm
IN TRIANGLE ADC
(using herons formula )
s=14+12+10/2
=36/2. =18
area of triangle ADC=√s(s-a)(s-b)(s-c)
=√18(18-14)(18-12)(18-10)
=√18×4×6×8
=√2×3×3×2×2×2×3×2×2×2
=2×3×2×2 √3×2
=24√6cm^2.
area of quadrilateral=area of triangle ABC+ area of triangle ADC
=24+24√6
=24(1+√6)cm^2
Answer:
Step-by-step explanation:
Q.2. draw AB=6cm,BC=8cm,CD=12cm,DA=14cm
join diagonal AC
(A.T.Q)the angle between first two sides is 90 degree
angle ABC=90 degree
area of triangle ABC=1/2×AB×BC
=1/2×6×8
=24cm ^2
In triangle ABC
(AC)^2=(AB)^2+(BC)^2
(AC)^2 =(6)^2+(8)^2
(AC)^2 =36+64
(AC)^2 =100
AC =√100
=10cm
IN TRIANGLE ADC
(using herons formula )
s=14+12+10/2
=36/2. =18
area of triangle ADC=√s(s-a)(s-b)(s-c)
=√18(18-14)(18-12)(18-10)
=√18×4×6×8
=√2×3×3×2×2×2×3×2×2×2
=2×3×2×2 √3×2
=24√6cm^2.
area of quadrilateral=area of triangle ABC+ area of triangle ADC
=24+24√6
=24(1+√6)cm^2
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