Question

Sumof two digit no. And reverse of it us 22 times the difference of the digit of the number .Find the two digit no.

Answer 1

Answer:

Get two digit no. by putting positive integers 3y = x

Step-by-step explanation:

Let two digit number be 10x+y where y is the unit digit and x is the ten's digit.  Let x>y

Reverse of two digit number = 10y + x

According to the question,

10 x + y +10 y +x = 22( x-y)

11 x + 11 y = 22 (x-y)

11 (x+y) = 22 (x-y)

x+y = 2 (x-y)

x+y = 2 x - 2 y

3y = 2x - x

3y = x

There are so many numbers are possible, which satisfy the condition 3y= x and above equation