Math, asked by kakoravansh, 6 months ago

sumofseries+1________+n is

Answers

Answered by Anonymous
1

Answer:

n(n+1)/2

Step-by-step explanation:

Sum of series of sum of natural numbers upto n,

i.e 1+2+3+4+.........+n = n(n+1)/2

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Answered by Anonymous
0

Answer:

Sn =  \frac{n(n + 1)}{2}

Step-by-step explanation:

Series: 1 + 2 + 3 + 4 + 5 + 6....... +n

Clearly this series is an Arithmetic Progression with:

First term (a) = 1

Last term (b) = n

Common Difference (d) = 2-1 = 1

No. of terms (n) = n

So,

Sum upto n terms = Sn = n/2[a + b]

=> Sn = n/2(1 + n)

Thus,

Sum of the given series is:

Sn =  \frac{n(n + 1)}{2}

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