sumplify y(y-3) +2 for y=1
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Answered by
0
Answer:
y3 – 5y2) ÷ Y × (y – 1) = ((y3 – 5y2)/y) × (y – 1)
= (y2 – 5y) × (y – 1) = y2 (y – 1) – 5y(y -1) = y3 – y2 – 5y2 + 5y
= y3 – 6y2 + 5y
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Answered by
1
Answer:
-4
Step-by-step explanation:
1×(1-3)+2=1×(-2)+2=-4
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