Math, asked by SumanaAnkam, 12 days ago

sumplify y(y-3) +2 for y=1​

Answers

Answered by rakeshkumar993153
0

Answer:

y3 – 5y2) ÷ Y × (y – 1) = ((y3 – 5y2)/y) × (y – 1)

= (y2 – 5y) × (y – 1) = y2 (y – 1) – 5y(y -1) = y3 – y2 – 5y2 + 5y

= y3 – 6y2 + 5y

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Answered by sandhyachitra234
1

Answer:

-4

Step-by-step explanation:

1×(1-3)+2=1×(-2)+2=-4

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