Math, asked by ekalavyaachanta, 1 year ago

Suneel completes a work in 4 days where as Dinesh completes the work in 6 days,Ramesh works one and half times as fast as Suneel how many days it will take for the three together to complete the work?

Answers

Answered by kvnmurty

productivity of Suneel per day: 1/4
Productivity of Dinesh per day : 1/6
productivity of Ramesh per day: 1.5 * 1/4 = 3/8

Total productivity of all = 1/4 + 1/6 + 3/8 per day
= 19/24

So all of them together will finish the complete work in 24/19 days.

ekalavyaachanta: sir how do u get 1/5 here

kvnmurty: one and half times means multiply with 1.5

kvnmurty: which class r u in ?

ekalavyaachanta: i'm preparing for bank exams sir..........i need ur guidance sir.non maths background sir

ekalavyaachanta: sir in my earlier question also u multiply 4/5 with 1/36 but i could not understand sir can u pls tell me the concept over there?

ekalavyaachanta: k now after seeing twice i understood sir

AcharyaVII: Do you really have doubts with these type of questions?

kvnmurty: These steps seem quite detailed and involve simple arithmetic.. One needs to read the question and see the answer. It will be easy to understand.

Answered by AcharyaVII

Suneel's 1 day's work=1/4
Dinesh's 1 day's work=1/6
Since Ramesh is 3/2 times faster than Dinesh,
Ramesh's 1 day's work=1/4*3/2=3/8
Working together, part of work done by them in 1 day=1/4+1/6+3/8
=(6+4+9)/24
=19/24.
Therefore they all will complete the work in 1/(19/24) days ,i.e.
24/19 days

kvnmurty: Ramesh is not 3/2 times faster than Suneel. That is not the correct way. Please see question. Ramesh is 3/2 times as fast as suneel.

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