Suneel deposited 10000 Rs in a bank. The bank gave an interest of 10% p.a. Suneel got 13310 Rs on completion of the term. Form how much time did suneel keep the money in the bank?
Answers
Answer:
ANSWER
According to the given question
Intersect per year =10,000×5 %
=10,000×
100
5
=500
Now,
Amount in I
st
years =10,000
Amount in 2
nd
year =10,000+intersect
=10,000+500=10,500
Amount in 3
rd
year =10,500+Intersect
=10,500+500=11,000
Then our series becomes
10,000,10,500,11000........
This is an AP
where a=10,000
d=10,500−10,000=500
time (n)=15 year
Then,
Amount in 15
th
year =a+(n−1)d
=10,000+(15−1)×500
=10,000+14×500
10,000+7000
17,000
Thus amount in 15
th
year in Rs.17,000
Amount of per 20 year =a
n
=a+(n−1)d
10,000+(21−1)×500
10,000+10,000
20,000
Thus, the amount in 20
th
years is
Rs.⇒20,000/−
Hence, this is the answer.
According to the given question
Intersect per year =10,000×5 %
=10,000×1005
=500
Now,
Amount in Ist years =10,000
Amount in 2nd year =10,000+intersect
=10,000+500=10,500
Amount in 3rd year =10,500+Intersect
=10,500+500=11,000
Then our series becomes
10,000,10,500,11000........
This is an AP
where a=10,000
d=10,500−10,000=500
time (n)=15 year
Then,
Amount in 15th year =a+(n−1)d
=10,000+(15−1)×500
=10,000+14×500
10,000+7000
17,000
Thus amount in 15th year in Rs.17,000
Amount of per 20 year =an
=a+(n−1)d
10,000+(21−1)× 500
10,000+10,000
20,000
Thus, the amount in 20th years is
Rs.⇒20,000/−
Hence, this is the answer.