Question

- Sunil completes a work in 4 days, whereas Dinesh completes the work in 6 days. Ramesh works 1 1/2 times
as fast as Sunil. The three together can complete the work in :
A days
B. 1 days
C. 1 days
D. 1 days
12​

Answer 1

Sunil's 1 day work = 1/4

Dinesh's 1 day work = 1/6

Ramesh's 1 day work = 3/2 times Sunil's work 1/4 × 3/2 = 3/8

Sum of work done by all in day 1/4+1/6+3/8=

(6+4+9)/24 19/24

So to complete the work together they will need, 24/19 days.

Answer 2

Answer:

12.6days

Step-by-step explanation:

we know efficiency is inversely proportional to time

s e/r e =r t/s t

1/(3/2) =R t/4

R time=2.6 days or 26/10 days

given sunil takes 4 and dinesh takes 6 days

so 1 day work of these guys is 1/4 , 1/6  and 10/26

add all these we get reuired answer

1/4 + 1/6+ 10/26 =10/126=12.6 days

MARK AS BRAINIEST BROoooooooo