Sunil deposited Rs. 8000 at the end of each year for 2 years, in a bank. Find the amourt that he recered at 10% pa. rate of compound interest
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Answer:
5
,144.25
Explanation:
We know that amount A at the end of n years at the rate of R% per annum is given by A=P(1+R/100)n
Given P=8000
R=18%
n=3years
Now, A=P(1+R/100)n
⇒ A=8000(1+18/100)3
⇒ A=8000(
100
100+18
)3
⇒ A=8000(
100
118
)3
⇒ A=8000.
100
254
⇒ A=Rs.13,14425
And CI=A−P=13,14425−8000
CI=5,14425
∴ so, the answer is “5,144.25”
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