Sunil gave 1/3 of his wealth to his wife and 2/5 to his son. If he now has ₹ 24000 left, then take the total value of his property.
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Total value of Sunil's property=Rs.90,000.
Step-by-step explanation:
Given:-
Sunil gave 1/3 of his wealth to his wife and 2/5 to his son. If he now has ₹ 24000 left,
To find:-
Find the total value of his property.
Solution:-
Let total value of Sunil's property be Rs. X
Amount given to his wife=1/3 of X=X/3
Amount given to his son=2/5 of X=2X/5
Total amount given his wife and son
=>(X/3)+(2X/5)
LCM of 3 and 5=15
=>(5X+6X)/15
=>11X/15
Remaining amount =X-(11X/15)
=>(15X-11X)/15
=>4X/15
Given that He has remaining amount=24000
=>4X/15=24000
=>4X=24000×15
=>X=24000×15/4
=>X=6000×15
=>X=90000
Answer:-
Total value of Sunil's property=Rs.90,000.
Check:-
Amount given to his wife=90000/3=30000
Amount given to his son=90000×2/5
=>18000×2=36000
Total amount given his wife and Son
=>30000+36000=66000
Remaining amount=90000-66000=24000
Verified ✅
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