Math, asked by vivek167075, 11 months ago

Sunil's mother's present age is six times the Sunil's age. After seven years, he will be
mother's age. What are their present ages?​

Answers

Answered by hskavitha11
2

Answer:

Actually this after 8 years u solve it by applying 6 by same method u will surely get the required answer

Assume that Sunil's present age = x.

Then mother's present age = 3x + x = 4x

After 8 years, mother age = 2 ½ times of Sunils' age

=> (4x+8) = 2½ * (x+8)

=> 4x + 8 = (5/2) * (x + 8)

=> 8x + 16 = 5x+ 40

=> 3x = 40-16 = 24

=> x = 24/3 = 8

After further 8 years,

Sunil's age = x + 8+ 8 = 8+8+8 = 24

Mothet's age = 4x + 8 + 8 = 48

Mother's age/Sunil's age = 48/24 = 2

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