Sunil takes 5 days more than Anil to complete a certain work .4 days after starting the work, Anil left the work .The remaining work was done by Sunil in 5 days. Find how many days each will take to complete the work.
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Answer:
Step-by-step explanation:
Given:
Sunil = +5 days than Anil to complete a certain work.
4 days after starting the work , Anil left the work.
Remaining work was done by sunil = 5 days
To find:
The number of days each will take to complete the work.
Solution:
The number of days taken to complete the job ( Anil ) = x
Then,
The number of days taken to complete the job ( Sunil = x + 5
Anil in one day = 1 / x
Sunil in one day = 1 / ( x + 5 )
Working together,
For one day,
1 / x + 1 / ( x + 5 )
2x + 5 / x ( x + 5 )
4 days together and 5 days by sunil,
4 * ( 2x + 5 ) / ( x ( x + 5 ) + 5 * 1 / ( x + 5 ) = 1
Solving for x,
We get,
x = 10
Substituting,
Hence,
Work done by Anil = 10 days
Work done by Sunil = 15 days
Akanksha07:
Thanks dear.....
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