Sunil takes a loan of 8,000 at a compound interest rate of 5% per annum. Find the amount and compound interest for 2 years.
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Answered by
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820 is the answer .ok bro
see below for explanation
Step-by-step explanation:
c = p[(1+r/100)^t - 1]
8000 [(1+5/100)^2-1]
8000 [(21/20)^2 -1]
8000 (441/400 -1)
8000 (41/400)
8000 (41/400)
8000*41/400 = 820
follow me bro
Answered by
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Step-by-step explanation:
Principal= rupees 8000
Rate of interest= 5%p.a
Time period= 2 years
interest for the first year= 8000×5×1/100
= 400 rupees
amount at the end of the first year= (8000+400)= 8400 rupees
principal for the second year= 8400 rupees
interest for the second year= 8400×5×1/100
= 420 rupees
amount at the end of the the second year= (8400+420)= 8820 rupees
amount = 8820 rupees
compound interest= 8820-8000= 820 rupees
answer: 8820 rupees, 820 rupees
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