Math, asked by yasalathasri, 1 day ago

Sunil takes a loan of 8,000 at a compound interest rate of 5% per annum. Find the amount and compound interest for 2 years.

Answers

Answered by kumarrandhir41340
0

820 is the answer .ok bro

see below for explanation

Step-by-step explanation:

c = p[(1+r/100)^t - 1]

8000 [(1+5/100)^2-1]

8000 [(21/20)^2 -1]

8000 (441/400 -1)

8000 (41/400)

8000 (41/400)

8000*41/400 = 820

follow me bro

Answered by baishakhiSinha
0

Step-by-step explanation:

Principal= rupees 8000

Rate of interest= 5%p.a

Time period= 2 years

interest for the first year= 8000×5×1/100

= 400 rupees

amount at the end of the first year= (8000+400)= 8400 rupees

principal for the second year= 8400 rupees

interest for the second year= 8400×5×1/100

= 420 rupees

amount at the end of the the second year= (8400+420)= 8820 rupees

amount = 8820 rupees

compound interest= 8820-8000= 820 rupees

answer: 8820 rupees, 820 rupees

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