Sunita and her friend were standing at opposite corners of rectangular park of size 120 m
× 50 m. For meeting her friend Sunita followed the shortest route. Find the distance covered by Sunita in doing so.
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Answered by
2
here we have to find the diagonal of the park by Pythagoras method
Let a rectangular ground be ABCD
AB^2+BC^2=AC^2
120×120+50×50=AC^2
14400+2500=AC^2
√16900=AC
130=AC
therefore shortest distance is 130m
Let a rectangular ground be ABCD
AB^2+BC^2=AC^2
120×120+50×50=AC^2
14400+2500=AC^2
√16900=AC
130=AC
therefore shortest distance is 130m
vaibhav20:
Did you got it.
Answered by
4
As we know that Sunita and her friend were standing in a rectangular park. So the shortest distance from an opposite corner is the diagonal of the rectangle.
l=120m
b=50m
By using Pythagoras theorem
h²=l²+b²
h²=120²+50²
h²=14400+2500
h²=16900
h=130m
So the distance covered by Sunita to meet her friend is 130m.
l=120m
b=50m
By using Pythagoras theorem
h²=l²+b²
h²=120²+50²
h²=14400+2500
h²=16900
h=130m
So the distance covered by Sunita to meet her friend is 130m.
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