sunita and her friend were standing at oppsite corners of rectangular park of size 120m ×50m. for metting her friend sunita followed the shortest route.find the distance covered by sunita in doing so?
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In a triangle, the sum of two sides is always greater than the third side. To solve the problem use Pythagoras Theorem.
hypotenuse square = side square + side square
let the diagonal be shown by the variable x
x^2 = 120^2 + 50^2.
x^2 = 14400 + 2500
x^2 = 16900
x = square root of 16900
= 130 m
therefore the shortest distance is 130 m
hypotenuse square = side square + side square
let the diagonal be shown by the variable x
x^2 = 120^2 + 50^2.
x^2 = 14400 + 2500
x^2 = 16900
x = square root of 16900
= 130 m
therefore the shortest distance is 130 m
Answered by
1
Hello !
The path is rectangular and so the two friends are standing in two corners so the shortest distance to travel to meet each other will be a diagonal of the rectangle .
So the length and breadth are 120 m and 50 m respectively,
According to the Pythagoras theorem : -
Hypotenuse² = L²+B²
⇒ H² = 14400+2500
⇒ H² = 16900
⇒ H=√16900
H = 130 m
Hence , the shortest distance is 13 m.
I hope the answer is correct !
Please mark this answer as the best if u r satisfied!
Thank you !
Happy Holi !!
The path is rectangular and so the two friends are standing in two corners so the shortest distance to travel to meet each other will be a diagonal of the rectangle .
So the length and breadth are 120 m and 50 m respectively,
According to the Pythagoras theorem : -
Hypotenuse² = L²+B²
⇒ H² = 14400+2500
⇒ H² = 16900
⇒ H=√16900
H = 130 m
Hence , the shortest distance is 13 m.
I hope the answer is correct !
Please mark this answer as the best if u r satisfied!
Thank you !
Happy Holi !!
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