Sunita has 19 in fifty paise and twenty-five paise coins. She has twice as many twenty
five paise coins as she has fifty paise coins. How many coins of each kind does she
have?
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Answer:
let number of fifty paisa coins = x
number of twenty paisa coins = 2x
1 rupees = 100 paisa
9 rupees = 900 paisa
value of 'x' fifty paisa coins = 50x
value of '2x' twenty paisa coins = 40x
50x + 40x = 900
90x = 900
x = 900/90
.•. x = 10
Hence, no. of fifty paisa coins = 10
no. of twenty paisa coins = 20
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