Sunita has a recurring deposit account in a bank of rupees 2000 per month at the rate of 10% per annum. if she gets Rupees 83100 at the time of maturity, find the total time (in years) for with the account was held.
Answers
Answered by
0
Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
P=Rs.2000
R=10%
M.V=Rs.83100
I=P×
2×12
n(n+1)
×
100
R
∴I=25×
24
n(n+1)
×
100
10
=
3
25(n
2
+n)
MV=P×n+I
⇒83100=(2000×n)+
3
25
n
2
+
3
25
n
⇒83100=
3
6000n+25n
2
+25n
⇒83100×3=6000n+25n
2
+25n
⇒25n
2
+6025n−249300=0
Dividing by (25),
n
2
+241n−9972=0
⇒(n−36)(n+272)=0
⇒n=36,orn=−272
But
′
n
′
can not be negative.
∴
n=36
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