Math, asked by cutiepie214, 10 months ago


Sunita has taken a three digit number as 258 and made it a Hii everyone ❤❤
good morning ❤❤.....





six digit number
258258. Then she divided this number with 7, 11 and 13 respectively. What is
the quotient got by Sunita? Is it the initial number taken by her? How is it
possible?​

Answers

Answered by johnkumarrr4
2

36894,23478,19866

Step-by-step explanation:

Given six digit number  258258 and divided by 7,11,13

258258/7=36894

258258/11=23478

258258/13=19866

Answered by manetho
1

Step-by-step explanation:

There is beauty in these type of numbers of the abcabc. These type of numbers are exactly divisible by 1001, produce the quotient of the abc.

⇒abcabc÷1001 = abc

⇒258258/1001= 258

Also, 7×11×13=1001

therefore, \frac{258258}{7\times11\times13} = 258.

This rule can be generalized as abab is divisible by 101, abcdabcd is divisible by 10001 and so on.

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