Math, asked by gnmpramod91131, 5 months ago

Sunita invested ₹50, 000 in mutual funds paying an interest 12% per annum . Find the amount he will get after 3 years if the interest is compounded annually. Also find the interest of the 3rd years.

Answers

Answered by sohelshaikh92
56

Answer:

Interest for the 1st year=50000*12/100=6000

Interest for the 2nd year=56000*12/100=6720

Interest for the 3rd year=62720*12/100=7526.4

Amount at the end of the 3rd year=62720+7526.4=70246.40

Step-by-step explanation:

hope it will help u

Answered by Sauron
122

Answer:

The amount after 3 years = 70,246.4

The interest of the 3rd year = 7526.40

Step-by-step explanation:

Principal (P) = ₹ 50, 000

Rate of interest (r) = 12 % per annum

Time (n) = 3 years

 P \: (1 \:  +  \frac{r}{100})^{n}

50,000 \:(1  \:  + \frac{12}{100}) ^{3}

50,000 \: ( \frac{112}{100}) ^{3}

50,000 \: ( \frac{56}{50})^{3}

50,000 \: ( \frac{28}{25})^{3}

 \frac{21,952 \:  \times  \: 50,000}{15,625}

70,246.4

The amount after 3 years = ₹ 70,246.4

____________________________

Amount after 2 years :

50,000 \: (1  \:  +  \:  \frac{12}{100})^{2}

50,000 \: ( \frac{112}{100})^{2}

 \frac{50,000 \:  \times  \: 784}{625}

62,720

Amount after 2 years = ₹ 62,720

____________________________

The interest of the 3rd year :

⇒ ₹ 70,246.4 - ₹ 62,720

₹ 7526.40

The interest of the 3rd year = ₹ 7526.40

Therefore,

The amount after 3 years = ₹ 70,246.4

The interest of the 3rd year = ₹ 7526.40

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