Sunita is 24 year older than her daughter Kavita. 6 year ago,sunita was thrice as old as Kavita. Find their present ages.
nilesh30:
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Answered by
71
Let the age of Kavita be x years.
Age of Sunita(x+24)yrs
6 years ago,
Age of Kavita=3(x-6)yrs
Age of Sunita=(x+24-6)yrs
3(x-6)=(x+24-6)
3x-18=x+18
3x-x=18+18
2x=36
x=18
So,Present age of Kavita=18 yrs.
Present age of Sunita=18+24=42yrs
Age of Sunita(x+24)yrs
6 years ago,
Age of Kavita=3(x-6)yrs
Age of Sunita=(x+24-6)yrs
3(x-6)=(x+24-6)
3x-18=x+18
3x-x=18+18
2x=36
x=18
So,Present age of Kavita=18 yrs.
Present age of Sunita=18+24=42yrs
Answered by
16
Here is your answer in the attachment
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6 years ago means what
-mean
6 yrs ago means before so it will be 3(x-6)=(x+24-6)
ok sorry for that and i correct it
ok
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