Question

Sunita is as twice as old as ashima. If 6years is subtracted from ashima age and 4 years added to sunita ago, then sunita will be 4 times ashima age how old were they two years ago

Answer 1

Let the age of Sunita be x and the age of Ashima be y.Sunita is twice as old as ashima⇒ x = 2y⇒ x - 2y = 0 ------------------ (1)Six years subtracted from Ashima's age = (y - 6)Four years added to Sunita's age = (x + 4)⇒ (x + 4) = 4(y - 6)⇒ (x + 4) = 4(y - 6)⇒ x + 4 = 4y - 24⇒ x - 4y = - 28 ------------------ (2)Solving equations (1) and (2), we get x = 28 and y = 14.Therefore, present age of Sunita is 28 years and the present age of Ashima is 14 years.Age of Sunita and Ashima two years ago was 26 years and 12 years respectively.