Sunita is as twice as old as Ashima. If six years is subtracted from Ashima's age and 4 years added to Sunitas age, then Sunita will be four times Ashima’s age. How old were they two years ago? (3 marks)
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let Sunita age be X and of ashima be y
as per question
X=2y
X+4=4(y-6)
put value of X
then 2y+4=4y-24
-2y=-28
y=14
X=2×14=28
as per question
X=2y
X+4=4(y-6)
put value of X
then 2y+4=4y-24
-2y=-28
y=14
X=2×14=28
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