Question

Sunita is as twice old as Ashima. if six years is subtracted from Ashima's age and four years added to Sunita's age, then Sunita will be four time Ashima's age. How old were they two years ago?

Answer 1

Hiii friend,


Let the age of ashima be X years.

Then the age of Sunita is 2X years

Before six years age of ashima = (X-6) years.

And,

After four years age of Sunita = (2X+4) years.

According to question,

2X+4 = 4(X-6) years

2X + 4 = 4X - 24

4X-2X = 4+24

2X = 28

X = 28/2 => 14 years.

Age of ashima = X = 14 years

And,

Age of Sunita = 2X = 2 × 14 = 28 years.


HOPE IT WILL HELP YOU...... :-)