Question

Sunita is half the age of her mother. Find their ages
( I ) after 4 years
( I ) before 3 years

Pls help, solve fast​

Answer 1

Answer:

let we take their ages as x

so after 4 years,

1/2x+x=4

1(1/2)x=4

(1/2)x=4

x=4×2

x=8

Before three years,

1/2x+x=-3

1(1/2)x=-3

(1/2)x=-3

x=-3×2

x=6

so sunita age is 1/2×8=4 years (after)

sunita age is 1/2×6=3 years (before)

Answer 2

Answer:

1/2 ×8=4(after)

1/2×6=3(before)