Question

Sunita is half the age of her mother Geeta. Find their ages After 4 years?

Answer 1

Answer:

Let the present age of Sunita be x years. The present age of her mother Geeta = 2(Sunita’s present age) = 2x years.

➡️ (i) After 4 years,

➡️Sunita’s age = (x + 4) years

➡️Geeta’s age = (2x + 4) years

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Answer 2

Aɴsᴡᴇʀ :-

Let the present age of Sunita be x years.

The present age of her mother Geeta =

2(Sunita’s present age) = 2x years.

2(Sunita’s present age) = 2x years. (i) After 4 years,

Sunita’s age = (x + 4) years

Geeta’s age = (2x + 4) years

(ii) Before 3 years,

Sunita’s age = (x – 3) years

Geeta’s age = (2x – 3) years.

Hope this is helpful for you !!