Question

Sunita is twice as old as ashima if 6 years is subtracted from ashima age and 4 years is added to Sunita age then sunita will be 4times ashima age. how old were the two years ago

Answer 1

Hey,

S=2A

4(A-6)=S+4

4A-24=2A+4

2A=28

A=14

So, ashima is 12years, sunitha is 26years before 2 years

☺️☺️

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!}}}$
Let the age of ashima is x years
So, The age of Sunita is 2x years

If 6 years is subtracted to Ashima's age so her age is (x- 6) years

And,
4 years is added to Sunita's age so her
age is (2x+4) years

ATQ,$4(x - 6) = 2x + 4 \\ 4x - 24 = 2x + 4 \\ 4x - 2x = 4 + 24 \\ 2x = 28 \\ x = \frac{28}{2} \\ x = 14$
So The present age of Ashima is 14 years
and Sunita age is 2 x 14 =28 years

Two years ago
Ashima's age is 14 - 2 =12 years
and Sunita's age is 28 -2 = 26 years

$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope \:it\:helps\: you}}}}}}}}}}}}}}}$