Question

sunita is twice as old as ashima . If six years are subtracted from Ashima's age and 4 years are added to sunita's age then sunita will be 4 times as old as Ashima's age. how old were they 2 years ago ??​

Answer 1

Let the age of Sunita be x and the age of Ashima be y.

Sunita is twice as old as ashima

⇒ x = 2y

⇒ x - 2y = 0 ------------------ (1)

Six years subtracted from Ashima's age = (y - 6)

Four years added to Sunita's age = (x + 4)

⇒ (x + 4) = 4(y - 6)

⇒ (x + 4) = 4(y - 6)

⇒ x + 4 = 4y - 24

⇒ x - 4y = - 28 ------------------ (2)

Solving equations (1) and (2), we get x = 28 and y = 14.

Therefore, present age of Sunita is 28 years and the present age of Ashima is 14 years.

Age of Sunita and Ashima two years ago was 26 years and 12 years