Question

Sunita is twice as old as Ashima. If six years is subtracted from Ashima’s age and four years added to Sunita’s age, then Sunita will be 4 times Ashima’s age. How old was Ashima two years ago.

14
12
16
10

just ans

Answer 1

Hey !

Let the present age of Ashima = x

Given,

Sunita is twice as old as Ashima

=> Present age of Sunita = 2x

If six years is subtracted from Ashima’s age, then

Ashima's age => x -6

And four years added to Sunita’s age, then

Sunita's age => 2x+4

Sunita will be 4 times Ashima’s age.

=> 2x+4 = 4 × ( x-6)

=> 2x+4 = 4x -24

=> 2x = 28

=> x = 14

Present age of Ashima = 14

Ashima's age 2 years ago = Ashima's present age -2 = 14-2 = 12.

•°• 2 years ago, Ashima was 12 years old

Meowwww xD

Answer 2

Answer:

Ashima will be 12 years old.

Step-by-step explanation:

Solution :

Let Ashima's age be y

The age of Sunita will be 2y years.

According to the question,

If 6 years is subtracted from Ashima’s age and four years added to Sunita’s age, then Sunita will be 4 times Ashima’s age.

⇒ 4(y - 6) = 2y + 4

⇒ 4y - 24 = 2y + 4

⇒ 4y - 2y = 4 + 24

⇒ 2y = 28

⇒ y = 14

Present age of Ashima = 14 years

Ashima's age 2 years ago -

⇒ 14 - 2

⇒ 12

Ashima's age 2 years ago = 12 years

Therefore, Ashima will be 12 years old.