Question

Sunita is twice as old as Seema. If 6 years is subtracted from Seema’s age and 4 years added to Sunita’s age, then Sunita will be four times Seema’s age. How old were they two years ago?

Answer 1

Let Seema's age = y
Then, Sunita's age = 2y

According to the question,
=> 2y + 4  = 4(y-6)
=> 2y + 4  = 4y -24
=> 2y - 4y = - 24 - 4
=> - 2y      = -28
=> y          = - 28/- 2
=> y          = 14
Now, Seema's present age = y =14 years
         Sunita's Present age = 2y =14 x 2
                                           = 28 years
Therefore, Seema's two years ago = 14 - 2 = 12 years
                  Sunita's two years ago  = 28 - 2 = 26 years