sunita wants to cover her suitcase with a tarpaulin cloth .If it measures 80cm×40cm×25cm ,how many metres of tarpaulin of width 90cm is required to cover 100 such suitcases
Answers
Answered by
33
Total surface area of object =2(80*40+40*25+80*25)
=2(3200+1000+2000)
=2*6200
=12400
T. S. A=area of cloth
12400=h*90
H=12400/90
H=137.77
=2(3200+1000+2000)
=2*6200
=12400
T. S. A=area of cloth
12400=h*90
H=12400/90
H=137.77
Answered by
19
Dear student,
◆ Answer -
l = 13778 cm
● Explanation -
Total surface area of 1 suitcase is -
TSA = 2 (lb + lh + bh)
TSA = 2 (80×40 + 80×25 + 40×25)
TSA = 12400 cm^2
To cover one such suitcase, length of tarpaulin cloth required is -
x = 12400 / 90
x = 137.78
To cover such 100 suitcases, length of tarpaulin cloth required is -
l = 137.78 × 100
l = 13778 cm
Hence, total length of tarpaulin cloth required is 13778 cm.
Thanks dear. Hope this helps you...
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