Question

Sunitha is 24 years older than her daughter kavitha. 6 years ago Sunitha was thrice as old as Kavitha. Find their present ages

Answer 1

s=sunitha's age
k=kavitha's age


s is 24 older than k
s=24+k


6 years ago (s-6 and k-6), sunitha was thrise as old as kavita
s-6=3(k-6)

subsitute 24+k for s
24+k-6=3(k-6)
k+18=3(k-6)
distribute
k+18=3k-18
minus k both sides
18=2k-18
add 18 both sides
36=2k
divide by 2 both sides
18=k

sub back
s=24+k
s=24+18
s=42


sunitha is 42 years old
kavita is 18 years old

Answer 2

Step-by-step explanation:

S=sunitha's age

k=kavitha's age

s is 24 older than k

s=24+k

6 years ago (s-6 and k-6), sunitha was thrise as old as kavita

s-6=3(k-6)

subsitute 24+k for s

24+k-6=3(k-6)

k+18=3(k-6)

distribute

k+18=3k-18

minus k both sides

18=2k-18

add 18 both sides

36=2k

divide by 2 both sides

18=k

sub back

s=24+k

s=24+18

s=42

sunitha is 42 years old

kavita is 18 years old