Question

Sunitha is 24 years older than her daughter Kavitha. 6 years ago,Sunitha was thrice as old as Kavitha.find their present ages

Answer 1

Answer:

Sunita age=X+24yrs

let kavita age=X yrs

Step-by-step explanation:

3(X-6)=X+24-6

3X-18=X+18

3X-X=18+18

2X=36

X=36/2

X=18

SO SUNITA AGE=18+24=42

KAVITA AGE=18 YEARS

Answer 2

Answer:

Let Kavitha's present age be x years

Therefore,

Sunitha's present age = x+24 years

A.T.Q,

3(x-6) = x+24 - 6

or, 3×x - 3×6 = x+18

or, 3x - 18 = x+18

or, 3x-x = 18 + 18

or, 2x = 36

or, x = 36/2

or, x = 18

Answer :- Kavitha's present age = x = 18 years

Sunitha's present age = x+24 years

= 18 + 24 years

= 42 years