Question

sunlight is observed to focus a point 18.5 cm behind the lens. find the power of the lens in diopters

Answer 1

Explanation:

So we are told that sunlight focuses at a distance of 18 centimeters behind the lens. No, some like, as we know, comes from sun, which is practically at an infinite distance. So because we have a real image, which is behind the lens, the lens must be converging lens on. Hence, it is probably a convex. Since it is definitely a converted converge England. It is probably a con convex lens. No, we wanted the 1st 1 It's a converging lens. Now, for the second part of the question, we need to find the power in the honors. We know that power opulence is won by F F is the focal land, so that in this case we know from the lens makers formula is won by Denard. Distance off the object that's one by distance of the image because now you know that the object distance is infinity on the image distance is 18.5 centimeters. So that 0.185 which gives us five point. I'm sorry I couldn't order the center pitches in to meet us here. Obviously excuses.

Answer 2

Answer: 5.41 D

Explanation:

Since sunlight is observed to focus at a point 18.5 cm behind lens

We know that this lens is a Converging Lens.

(18.5 cm -> 0.185 m)

To find power we use the

EQ: P = 1/f

-- where p is power of the lens in diopters (D) and f is focal length (m)

= 1/fo + 1/f

= 1/infinity + 1/0.185

= 0 + 5.41 D

There for P = 5.41 in Diopters

Focal length is 0.185